The Dft And Fft
By the halving lemma, the list of values (30.10) consists not of n distinct values but only of the n/2 complex (n/2)th roots of unity, with each root occurring exactly twice. Therefore, the polynomials A[0] and A[1] of degree-bound n/2 are recursively evaluated at the n/2 complex (n/2)th roots of unity. These subproblems have exactly the same form as the original problem, but are half the size. We have now successfully divided an n-element DFTn computation into two n/2-element DFTn/2 computations. This decomposition is the basis for the following recursive FFT algorithm, which computes the DFT of an n-element vector a = (a0, a1,..., an-1), where n is a power of 2.
RECURSIVE-FFT(a) 1 n ← length[a] ▹ n is a power of 2. 2 if n = 1 3 then return a 4 wn ← eπi/n 5 w ← 1 6 a[0] ← (a0, a2,..., an-2) 7 a[1] ← (a1, a3,..., an-1) 8 y[0] ← RECURSIVE-FFT(a[0]) 9 y[1] RECURSIVE-FFT(a[1]) 10 for k ← 0 to n/2 - 1 11 do
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12
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13 w ← w wn 14 return y ▹ y is assumed to be a column vector.
The RECURSIVE-FFT procedure works as follows. Lines 2 -3 represent the basis of the recursion; the DFT of one element is the element itself, since in this case
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Lines 6 -7 define the coefficient vectors for the polynomials A[0] and A[1]. Lines 4, 5, and 13 guarantee that w is updated properly so that whenever lines 11 -12 are executed, . (Keeping a running value of w from iteration to iteration saves time over computing
from scratch each time through the for loop.) Lines 8-9 perform the recursive DFTn/2 computations, setting, for k = 0, 1,..., n/2 - 1,
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or, since by the cancellation lemma,
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Lines 11-12 combine the results of the recursive DFTn/2 calculations. For y0, y1,..., yn/2-1, line 11 yields
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For yn/2, yn/2 1,..., yn-1, letting k = 0, 1,..., n/2 - 1, line 12 yields
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Thus, the vector y returned by RECURSIVE-FFT is indeed the DFT of the input vector a.