←
Maths for Engineers - 2
Linear Equation With Constant Coefficients
Linear Equation with Constant Coefficients-1:
3. Solve
Solution: Dx 2y = -sint..............(1)
-2x Dy = cost..............(2)
1×2 (2) × D ⇒ 4y D2y = -2sint D(cost)
⇒ (D2 4) = -3 sint
m2 4 = 0, m = ±i2
C.F = A cos 2t B sin 2t
P.I =
y = A cos 2t B sin 2t - sint
∴ x = A cos 2t B sin 2t - cost
y = A cos 2t B sin 2t - sint.
4. Solve
Solution: Dx (-D 2)y = cos 2t......(1)
(D - 2)x Dy = sin 2t......(2)
Eliminating y from (1) and (2)
(D2 - 2D 2)x = -2 sin 2t cos 2t
R.H.S = 0 ⇒ m2 - 2m 2 = 0
m = 1±i