# Brewster's Angle

............................................(5)

will be negative and its magnitude will increase with the angle of incidence taking the value of 1 at as shown in fig 2. the negative sign in the region of inequality (3) indicate that the electric field for the reflected wave is out of phase with the corresponding incident wave.

For the angle of incidence satisfying equation (4), the reflected light is purely s polarized. This particular angle of incidence denoted by is termed as the **Brewster angle **and from equation (8) it can be easily shown .

................................................(6)

In case if the first medium happen to be other than air than than equation (6) can be shown to be modified as

**Thus if an electromagnetic wave falls at an Brewster's angle then the reflected light is S polorized. Hence this is one of the way to generate the polorized light. **