# Problems On Method Of Undetermined Coefficients

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**Problems on Method of Undetermined Coefficients:**

**3.** Solve using the method of undetermined method:

y'' - 5y' 6y = sin 2x.

**Solution:** we have (D^{2} - 5D 6)y = sin 2x

A.E is m^{2} - 5m 6 = 0

(m-2) (m-3) = 0

∴ m = 2,3

We assume for the P.I in the form

We have to find 'a' and 'b' such that

Now,

Comparing the coefficient we get:

Solving we get;

From the above equations:

**4.** Solve by the method of undetermined coefficient:

y'' y' - 2y = x sinx

**Solution: We can solve this equation with the help of above metod.
**